b^2-10b-8=3

Solution for b^2-10b-8=3 equation:

Simplifying
b2 + -10b + -8 = 3

Reorder the terms:
-8 + -10b + b2 = 3

Solving
-8 + -10b + b2 = 3

Solving for variable 'b'.

Reorder the terms:
-8 + -3 + -10b + b2 = 3 + -3

Combine like terms: -8 + -3 = -11
-11 + -10b + b2 = 3 + -3

Combine like terms: 3 + -3 = 0
-11 + -10b + b2 = 0

Factor a trinomial.
(-1 + -1b)(11 + -1b) = 0

Subproblem 1
Set the factor '(-1 + -1b)' equal to zero and attempt to solve:

Simplifying
-1 + -1b = 0

Solving
-1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = 0 + 1
-1b = 0 + 1

Combine like terms: 0 + 1 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1
Subproblem 2
Set the factor '(11 + -1b)' equal to zero and attempt to solve:

Simplifying
11 + -1b = 0

Solving
11 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -1b = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -1b = 0 + -11
-1b = 0 + -11

Combine like terms: 0 + -11 = -11
-1b = -11

Divide each side by '-1'.
b = 11

Simplifying
b = 11
Solution
b = {-1, 11}